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Byju's Answer
Standard VII
Mathematics
Pythagoras Theorem
A Micro-gram ...
Question
(A) Micro-gram
(
m
.
m
.
)
−
3
=
.
.
.
.
.
.
.
k
g
m
−
3
(B) Nanometer min
−
2
=
.
.
.
.
.
.
m
s
e
c
−
2
(C)
k
g
f
c
m
−
2
=
.
.
.
.
.
.
N
m
−
2
(kgf = 10 N)
(D)
k
g
m
−
2
s
−
2
=
.
.
.
.
.
g
r
c
m
2
S
−
2
Open in App
Solution
(
A
)
M
i
c
r
o
−
g
r
a
m
(
m
.
m
.
)
−
3
=
10
−
9
(
10
−
3
)
3
k
g
m
−
3
=
1
k
g
m
−
3
(
B
)
N
a
n
o
m
e
t
e
r
m
i
n
−
2
=
10
−
9
(
60
)
2
m
s
e
c
−
2
=
1
36
×
10
−
11
m
s
e
c
−
2
(
C
)
k
g
f
c
m
−
2
=
10
(
10
−
2
)
2
N
m
−
2
=
10
5
N
m
−
2
(
D
)
k
g
m
−
2
s
−
2
=
10
3
(
10
2
)
2
g
c
m
2
s
−
2
=
10
−
1
g
c
m
2
s
−
2
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