The correct options are
B 10 V range with
200 kΩ resistance in series
C 5 mA range with
1 Ω resistance in parallel
To convert a galvanometer into a voltmeter of certain range say
V, a high resistance
R is connected in series with the galvanometer so that current passing through the galvanometer of resistance
G becomes equal to its full scale deflection value
Ig.
This is possible only if,
V=Ig(G+R) i.e.,R=VIg−G
For
V=10 V,
Ig=50 μA ,
G=100 Ω
R=1050×10−6−100
R≈200 kΩ
Hence, (b) option is the correct answer.
To convert a galvanometer into an ammeter of a certain range say
I, a small resistance
S (called shunt) is connected in a parallel with the galvanometer so that the current passing through the galvanometer of resistance
G becomes equal to its full scale deflection value
Ig.
This is possible only if,
IgG=(I−Ig)S
∴S=Ig(I−Ig)G
For ,
Ig=50 μA ,
G=100 Ω and
I=5 mA
S=50×10−6(5×10−3−0.050×10−3)×100
∴S≈1 Ω
Hence option (c) is also correct.
Why this question ?
Key concept :
To convert a galvanometer into a voltmeter of certain range say V, a high resistance R is connected in series with the galvanometer.
To convert a galvanometer into an ammeter, a small resistance S (called shunt) is connected in parallel with the galvanometer |
.