The correct options are
B range 10 v, with a (2×105−100)Ω resistance in series
C range 5 mA, with a 1.01Ω resistance in parallel
Given
Rg=100Ω
Ig=50×10−6A
To use given galvanometer as an voltmeter a large resistanceRv should be connect in series to it.
(i) Consider, V=50 V,
Rv=VIg−Rg
Rv=5050×10−6−100
Rv=100000−100=99900Ω
(ii) Consider, V=10 V,
Rv=VIg−Rg
Rv=1050×10−6−100
Rv=(0.2×106−100)Ω
Rv=(2×105−100)Ω
To use given galvanometer as an ammeter a shunt resistance S should be connect in parallel to it.
(i) Consider, I=5 mA
S=RgIgI−Ig
S=100×50×10−65×10−3−50×10−6
S=5×10−35×10−3−0.05×10−3
S=5×10−34.95×10−3
S=1.01Ω
(ii) Consider, I=10 mA
S=RgIgI−Ig
S=100×50×10−610×10−3−50×10−6
S=5×10−310×10−3−0.05×10−3
S=5×10−39.95×10−3
S=0.502Ω