A micrometer screw gauge has a negative error of $7$ divisions. While measuring the diameter of a wire, the reading on the main scale is $2$ divisions and $78 t h$ circular scale division, coincides with baseline. The number of divisions on the main scale per centimetre is $10$ and the circular scale has 100 divisions. Find the pitch of the screw.

0.01 mm

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0.01 cm

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0.1 cm

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0.001 mm

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Solution

The correct option is A 0.01 mm
As the number of divisions on main scale are 10 to a centimeter, so the smallest division on main scale will be $1 m m$ and it will be the pitch (p) of the screw gauge. The number of circular divisions is $n = 100$ .
The least count of a screw gauge is $L . C = p / n = 1 m m / 100 = 0.01 m m$

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The correct option is A 0.01 mmAs the number of divisions on main scale are 10 to a centimeter, so the smallest division on main scale will be 1mm and it will be the pitch (p) of the screw gauge. The number of circular divisions is n=100.The least count of a screw gauge is L.C=p/n=1mm/100=0.01mm