A microscope is focused on a mark on a piece of paper and then a slab of glass of thickness 3 cm and refractive index 1.5 is placed over the mark. How should the microscope be moved to get the mark in focus again ?

1 cm upward

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4.5 cm downward

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1 cm downward

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2 cm upward

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Solution

The correct option is A 1 cm upward
Shifting in microscope = upward shifting in mark

= $t (1 - \frac{1}{μ})$ = $3 (1 - \frac{1}{1.5})$ = 1 cm

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A microscope is focused on a mark on a piece of paper and then a slab of glass of thickness 3 cm and refractive index 1.5 is placed over the mark. How should the microscope be moved to get the mark in focus again ?

The correct option is A 1 cm upwardShifting in microscope = upward shifting in mark= t(1−1μ) = 3(1−11.5) = 1 cm

The correct option is A 1 cm upward
Shifting in microscope = upward shifting in mark

= $t (1 - \frac{1}{μ})$ = $3 (1 - \frac{1}{1.5})$ = 1 cm