Question

A microscopic particle of mass ${10}^{-12}$ kg is moving with a velocity of ${10}^2$ m/s. Then the de-Broglie wavelength associated with the particle is

• A. $6.6\times {10}^{-24}m$
• B. $6.6\times {10}^{34}m$
• C. $3.3\times {10}^{24}m$
• D. $0$

Answer 1

The correct option is A $6.6\times {10}^{-24}m$

$\lambda =\frac{h}{m\nu }$

$=\frac{6.6\times {10}^{-34}}{{10}^{-12}\times {10}^2}$

$=6.6\times {10}^{-24}m$

So, the answer is option (A).