A mild-steel wire of length 2L and cross-sectional area A is stretched, well within elastic limit, horizontally between two pillars, A mass m is suspended from the midpoint of the wire. Strain in the wire is
A
x22L2
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B
xL
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C
x2L
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D
x22L
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Solution
The correct option is Ax22L2 Change in length, ΔL = AC - AO =[L2+x2]12−L=L[1+12x2L2]−L=x22L Longitudinal strain =ΔLL=x2/2LL=x22L2