Given that, height of milk container (h) = 16 cm.
Radius of lower end of milk container (r) = 8 cm
And radius of upper end of milk container (R) = 20 cm
∴ Volume of the milk container made of metal sheet in the form of a frustum of a cone
=πh3(R2+r2+Rr)=227×163[(20)2+(8)2+20×8]=22×1621(400+64+160)=22×16×62421=21964821[∵1L=100 cm3]=10459.42 cm3=10.45942 L
So, volume of the milk container is 10459 . 42 cm3
∵ Cost 1 L milk = Rs 22
∵ Cost of 10.45942 L milk =22×10.45942 = Rs 230.12
Hence, the required cost of milk is Rs 230.12