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Question

A milkman sold milk at two different rates depending on how much water he added to them. One of the types in which he added no water, he sold it for 101 per kilogram. The one in which he added water he sold it for 81 per kilogram. He sold 4 kilograms of pure milk and 9 kilograms in which water was added. Find his net monthly income. [4 MARKS]

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Solution

Concept: 1 Mark
Steps: 2 Marks
Answer: 1 Mark

Given that :
The cost of pure milk = 101 per kilogram
The cost of milk in which water was added= 81 per kilogram
Amount of pure milk he sold = 4 kilograms
Amount of impure milk he sold = 9 kilograms
His net income = 101×4 + 81×9 = (100+1)×4 + (80 + 1)×(10-1)
= 400 + 4 + 800 - 80 + 10- 1 = 1133


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