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Question

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5 by weight. 2.8 g of the mineral on heating lost 1.32 g of CO2. What is the % by weight of the other metal?

A
87.5
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B
35.71
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C
65.11
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D
23.21
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Solution

The correct option is D 23.21
Let two equimolar carbonates are ACO3 and BCO3
Weight of metal A=2.8×12.5100=2.8×0.125=0.35 g
ACO3+BCO3AO+BO+2CO2
Total two moles CO23 provide 2 moles of CO2 or 60 g CO23 provide 44 g of CO2
Total mass of CO23 required to be produced
1.32 g of CO2=6044×1.32=1.8 g
weight of metal (A+B)=2.81.8=1 g
weight of B=10.35=0.65 g
% of B=0.652.80×100=23.21

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