A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 20% by weight. 3.0g of the mineral on heating lost 1.1g of CO2. What is the % by weight of the other metal?
A
70%
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B
33%
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C
67%
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D
30%
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Solution
The correct option is D30% Let, two equimolar carbonates are ACO3andBCO3 WeightofmetalA=3×0.20=0.6gACO3+BCO3→AO+BO+2CO2 Total two moles CO2−3 provide 2 moles ofCO2 or one moleCO2−3provide 1 mole ofCO2 or 60gCO2−3 provide44gofCO2 Total mass ofCO2−3required to produce 1.1 g of CO2=6044×1.1=1.5g weightofmetal(A+B)=3−1.5=1.5g weightofB=1.5−0.6=0.9g %ofB=0.93×100=30%