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Question

A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 20% by weight. 3.0 g of the mineral on heating lost 1.1 g of CO2. What is the % by weight of the other metal?

A
70%
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B
33%
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C
67%
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D
30%
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Solution

The correct option is D 30%
Let, two equimolar carbonates are ACO3 and BCO3
Weight of metal A=3×0.20=0.6 gACO3+BCO3AO+BO+2CO2
Total two moles CO23 provide 2 moles of CO2
or
one mole CO23 provide 1 mole of CO2
or
60 g CO23 provide 44 g of CO2
Total mass of CO23 required to produce 1.1 g of CO2=6044×1.1=1.5 g
weight of metal (A+B)=31.5=1.5 g
weight of B=1.50.6=0.9 g
% of B=0.93×100=30%

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