Question

A mirror is broken into two parts and these parts are separated by a distance of 1 cm as shown in figure The focal length of the mirror is 10 cm Find the location of the images (in cm) formed by the two parts of mirror The object is midway between the two principal axes _________.

• A. 1, 1
• B. 1, 2
• C. 2, 2
• D. 0.5, 1

Answer 1

The correct option is A 1, 1

$\frac{1}{-10}=\frac{1}{v}+\frac{1}{(-15)}$

$\frac{1}{v}=\frac{1}{15}-\frac{1}{10}$

$\frac{1}{v}=\frac{2-3}{30}$

$v=-30cm$

magnification $=\frac{-(-30)}{-15}=-2$

(1) $\frac{h_1}{-\frac{1}{2}}=-2\Rightarrow h_1=1cm$

(2) $\frac{h_i}{\frac{1}{2}}=-2\Rightarrow h_i=-1cm$

so location of images is 1,1

option $A$ is correst