wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A missile has been fired with an initial speed u. If the speed is tripled, what will be the corresponding change in its kinetic energy?


A

Remains same

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

Decreases thrice

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Increases nine times

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

Increases thrice

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

Increases nine times


The mathematical expression for Kinetic Energy of an object is K.E.=12mv2, where m is the mass of the object, v is the speed of the object.

Here, kinetic energy is directly proportional to the square of the speed.

Let initial speed be v1

Initial kinetic energy, K.E1=12mv12

Let Final speed be v2 = 3v1

so, final kinetic energy K.E2=12mv22


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon