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Concentration Terms

A mixture con...

Question

A mixture consisting of $0.10$ moles of $N_{2}$ , $0.05$ moles of $O_{2}$ and $0.20$ moles of $C H_{4}$ and an unknown amount of $C O_{2}$ occupied a volume of $9.6 L$ at $27^{o} C$ and $1.0$ atm pressure. How many moles of $C O_{2}$ are there in this sample?

A

0.04 m o l

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B

0.39 m o l

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C

0.05 m o l

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D

0.10 m o l

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Solution

The correct option is A $0.04 m o l$
Using Ideal gas equation
$P V = n R T$
$n = \frac{P V}{R T} = \frac{9.6 L \times 1.0 a t m}{0.0821 \times 300 K (a t m L K^{- 1} {m o l}^{- 1})}$
$n = 0.389$ moles
$n = n_{{C o}_{2}} + n_{N_{2}} + n_{O_{2}} + n_{{C H}_{4}}$
$n = n_{{C O}_{2}} + 0.1 + 0.05 + 0.2$
$0.389 = n_{{C O}_{2}} + 0.1 + 0.05 + 0.2$
$n_{{C O}_{2}} = 0.04$ moles

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