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Question

A mixture containing 0.84 gm of NaHCO3,4.0 gm of NaOH and 10.6 gm of Na2CO3 is dissolved in water and the resulting solution is titrated with 0.5 M HCl solution. Identify the option(s) which is/ are correct.

A
The volume of HCl used when phenolpthalein is used as an indicator is 400 ml
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B
The volume of HCl used when methyl orange is used as an indicator is 400 ml
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C
The volume of HCl further used when methyl orange is used as an indicator in a solution titrated with phenolpthalein is 200 ml
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D
The volume of HCl used when phenolphthalein is used as indicator after titrating with methyl orange is 200 ml
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Solution

The correct option is A The volume of HCl used when phenolpthalein is used as an indicator is 400 ml
0.84gNaHCO3=0.01 moles
4gNaOH=0.1 moles
10.6Na2CO3=0.1 moles
with hph indicator we can detect until NaOH consumed and Na2CO3NaHCO3 conversion.
Hence 0.2 moles of acid needed
0.2=0.5×VlitVlit=0.4lit
=400ml
With methyl orange we detect total conversion
(0.1)+(0.01)+(0.1)×2=0.31
0.31=0.5M×vlit
vlit=0.62 lit
=620ml

1071576_764776_ans_16878c6607314a69809336ed263feb03.jpg

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