A mixture containing 1-6 g of O2- 1-4 g of N2 and 0-4 g of He occupies a volume of 10 L at 27- C- Calculate the partial pressure of each component of the mixture-

P_He nbsp; nbsp;= 0.246 atm, P_O_2 nbsp;= P_N_2 nbsp; = 0.123 atm Given that V =10 L , T = 27^∘ nbsp;C=300 K nbsp; The number of moles are ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Chemistry

Dalton's Law of Partial Pressures

A mixture con...

Question

A mixture containing 1.6 g of $O_{2}$ , 1.4 g of $N_{2}$ and 0.4 g of $H e$ occupies a volume of $10 L$ at $27^{\circ} C$ . Calculate the partial pressure of each component of the mixture.

$P_{N_{2}} = 0.500 a t m$
$P_{O_{2}} = 0.25 a t m$
$P_{H e} = 0.25 a t m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$P_{N_{2}} = 0.246 a t m$
$P_{O_{2}} = 0.246 a t m$
$P_{H e} = 0.492 a t m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$P_{N_{2}} = 0.123 a t m$
$P_{O_{2}} = 0.123 a t m$
$P_{H e} = 0.246 a t m$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$P_{N_{2}} = 1 a t m$
$P_{O_{2}} = 1.123 a t m$
$P_{H e} = 2.246 a t m$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$P_{N_{2}} = 0.123 a t m$
$P_{O_{2}} = 0.123 a t m$
$P_{H e} = 0.246 a t m$

$P_{H e} = 0.246 a t m, P_{O_{2}} = P_{N_{2}} = 0.123 a t m$

Given that $V = 10 L$ , T = $27^{\circ} C = 300 K$
The number of moles are :-

$n_{H e} = \frac{0.4}{4} = 0.1$
$n_{N_{2}} = \frac{1.4}{28} = 0.05$
$n_{O_{2}} = \frac{1.6}{32} = 0.05$

therefore , the total number of moles = 0.1+0.05+0.05 = 0.2

Using the ideal gas equation PV = nRT $\Rightarrow P \times 10 = 0.2 \times 0.082 \times 300 \Rightarrow P = 0.492 a t m$

As partial pressure = total pressure $\times$ mole fraction , we have

$P_{H e} = 0.492 \times \frac{0.1}{0.2}$ = 0.246 atm

$P_{N_{2}} = 0.492 \times \frac{0.05}{0.2} = 0.123 a t m$

$P_{O_{2}} = 0.492 \times \frac{0.05}{0.2}$ = 0.123 atm

Suggest Corrections

Similar questions

A mixture containing 1.6 g of $O_{2}$ , 1.4 g of $N_{2}$ and 0.4 g of $H e$ occupies a volume of $10 L$ at $27^{\circ} C$ . Calculate the partial pressure of each component of the mixture.

Q. A vessel of volume 4 litres contains a mixture of 8g of

O_{2}

14 g of N2 and 22 g of

C O_{2}

27^{\circ} C

. The pressure exerted by the mixture is ?

Q. The density of a mixture of

O_{2}

and

N_{2}

at NTP is 1.3 g litre

^{- 1}

. Calculate partial pressure of

O_{2}

Q. Total pressure of a gaseous mixture containing

28 g N_{2}

and

16 g O_{2}

in a cylinder of volume

8.21 L

300 K

is:
[Given:

R = 0.0821 {L atm mol}^{- 1} K^{- 1}

]

Join BYJU'S Learning Program

A mixture containing 1.6 g of O2, 1.4 g of N2 and 0.4 g of He occupies a volume of 10 L at 27∘C. Calculate the partial pressure of each component of the mixture.

A mixture containing 1.6 g of $O_{2}$ , 1.4 g of $N_{2}$ and 0.4 g of $H e$ occupies a volume of $10 L$ at $27^{\circ} C$ . Calculate the partial pressure of each component of the mixture.