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Oxidation Number Method

A mixture con...

Question

A mixture containing 2 moles of $K_{2} C_{2} O_{4}$ and 4 moles of $K H C_{2} O_{4}$ titrated separately against $H_{2} C_{2} O_{4}$ and NaOH. The moles of acid and base required respectively to reach endpoint would be:

A

4 and 4

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B

2 and 6

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C

2 and 4

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D

1 and 4

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Solution

The correct option is C 2 and 4
$K_{2} {C r}_{2} O_{4} + H_{2} C_{2} O_{4} ⟶ 2 K H C_{2} O_{4}$
${K H C}_{2} O_{4} + H_{2} C_{2} O_{4} ⟶ {K H C}_{2} O_{4} + H_{2} C_{2} O_{4}$
$↪$ almost equivalent to no reaction interms of acid quantity.
Hence ${2 K}_{2} C_{2} O_{4}, {4 K H C}_{2} O_{4}$ needed $2$ moles $H_{2} C_{2} O_{4}$
$K_{2} C_{2} O_{4} + N a O H ⟶ \times$
${K H C}_{2} O_{4} + N a O H ⟶ N a K C_{2} O_{4} + H_{2} O$
Hence ${2 K}_{2} C_{2} O_{4}, {4 K H C}_{2} O_{4}$ needed $4$ moles of $N a O H$ .

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