In the mixture of
KCl and NaCl :
74.5 g of KCl requires 170 g of AgNO3 and
58.5 g of NaCl requires 170 g of AgNO3
And in 51mL of 0.1N solution :
weight of AgNO3 = 0.1×170×511000=0.867g
In solution weighing 0.3250g let us consider x gm KCl and the remaining 0.325−x gm is NaCl.
∴molesNaCl+molesKCl=molesAgNO3
∴x74.5+0.325−x58.5=0.867170
∴x=0.1240gm=weight of KCl in sample
∴0.201gm=weight of NaCl in sample
percentage of KCl=0.124×1000.325=38.19%
percentage of NaCl=0.201×1000.325=61.81%