A mixture contains 2 mole of helium $(C_{P} = 2.5 R, C_{V} = 1.5 R)$ and 3 mole of hydrogen $(C_{P} = 3.5 R, C_{V} = 2.5 R)$ . Calculate the values of $2 γ = ?$ for the mixture.

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Solution

We have calculated $C_{P} = 3 R$ and $C_{V} = 2 R$ for mixture.
Now, the value of $γ$ for the mixture $γ = \frac{C_{P}}{C_{V}}$
$∴$ $γ = \frac{3 R}{2 R} = 1.5$
Thus $2 γ = 2 \times 1.5 = 3$

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A mixture contains 2 mole of helium (CP=2.5R,CV=1.5R) and 3 mole of hydrogen (CP=3.5R,CV=2.5R). Calculate the values of 2γ=? for the mixture.

We have calculated CP=3R and CV=2R for mixture.Now, the value of γ for the mixture γ=CPCV∴ γ=3R2R=1.5Thus 2γ=2×1.5=3

A mixture contains 2 mole of helium $(C_{P} = 2.5 R, C_{V} = 1.5 R)$ and 3 mole of hydrogen $(C_{P} = 3.5 R, C_{V} = 2.5 R)$ . Calculate the values of $2 γ = ?$ for the mixture.

We have calculated $C_{P} = 3 R$ and $C_{V} = 2 R$ for mixture.
Now, the value of $γ$ for the mixture $γ = \frac{C_{P}}{C_{V}}$
$∴$ $γ = \frac{3 R}{2 R} = 1.5$
Thus $2 γ = 2 \times 1.5 = 3$