Question

A mixture contains sugar and water in the ratio of $2:11$. If it contains $4.6\mathrm{kg}$ of sugar, find the quantity of water in the mixture.

Answer 1

Calculation of the quantity of water:

Let the mixture contains $x$ kg of water. Then the corresponding proportional is $2:11::4.6:x$.

$$\begin{gathered} \Rightarrow 2:11=4.6:x(Changingtheproportionalitysignintoequalsign) \\ \Rightarrow \frac{2}{11}=\frac{4.6}{x} \\ \Rightarrow 2·x=4.6·11(Crossmultiplyingbothsides) \\ \Rightarrow x=\frac{4.6·11}{2}(Dividingbothsidesby2) \\ \therefore x=25.3 \end{gathered}$$

Final Answer: The mixture contains $25.3\mathrm{kg}$ of water.