A mixture of 0.1 M HCl and 0.2 M H2SO4 is titrated with 0.1 M NaOH. How much volume of NaOH is required for complete neutralization, if the initial volume of the acidic solution (V) is 10 mL?
The correct option is C 30 mL
n-factor(nf) for HCl, H2SO4 and NaOH are 1, 2 and 1 respectively.
So, for neutralization,
number of equivalents of acids = number of equivalents of base
(M1×V)+(2×M2×V)=M3×V′; where M1, M2 and M3 are concentrations of HCl, H2SO4 and NaOH respectively.
∴ volume of base required = 0.1×10+2×0.1×100.1=30 mL