A mixture of 1-chloropropane and 2-chloropane when treated with alcoholic $K O H$ gives:

prop-1-ene

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prop-2-ene

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a mixture of prop-1-ene and prop1-ene

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propanol

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Solution

The correct option is A prop-1-ene
The product we get after the reaction of chloropropane when treated with alcoholic $K O H$ is prop-1-ene. Therefore A is the correct option.

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Similar questions

How do you convert the following:

(i) Prop-1-ene to 1-fluoropropane

(ii) Chlorobenzene to 2-chlorotoluene

(iii) Ethanol to propanenitrile

What happens when

(i) n-butyl chloride is treated with alcoholic KOH?

(ii) 2, 4, 6-trinitrochlorobenzene is subjected to hydrolysis?

(iii) methyl chloride is treated with AgCN?

1 - p h e n y l - 2 - c h l o r o p r o p a n e

K O H

When Prop-1-ene is treated with HCl in the presence of peroxide we get:

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