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Question

A mixture of 1 mol of Al and 3 mol of Cl2 are allowed to react as:
2Al+3Cl22AlCl3
Find the mass of excess reagent left.

A
220 g
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B
115 g
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C
85 g
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D
106.5 g
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Solution

The correct option is D 106.5 g
2Al+3Cl22AlCl3
Initial number of moles of Al and Cl2 are 1 mol and 3 mol respectively

For Al,
Initial number of molesstoichiometric coefficient=12=0.5

For Cl2, Initial number of molesstoichiometric coefficient=33=1

According to the stoichiometry,
2 mole of Al reacts with 3 mole of Cl2
1 mole of Al will react with 1.5 mole of Cl2

Mass of the excess reagent left unreacted = 1.5 × molar mass of Cl2
=1.5×71=106.5 g

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