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Standard XII

Chemistry

Introduction to Le Chatelier's Principle

A mixture of ...

Question

A mixture of 1 mole of $P C l_{5}$ , 1 mole of $P C l_{3}$ and 0.5 mole of $C l_{2}$ are taken in a closed container. At equilibrium, if the container contains 0.3 moles of $C l_{2}$ , the number of moles of $P C l_{5}$ is:

1.3

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0.8

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0.7

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1.2

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Solution

The correct option is D 1.2
$P C l_{5} P C l_{3} + C l_{2} I n i t i a l m o l e s 11 0.5 A t e q u i 1 + 0.2 1 - 0.2 0.5 - 0.2 A m o u n t o f P C l_{5} = 1 + 0.2 = 1.2 m o l e$

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Similar questions

Q. Three moles of

P {C l}_{5}

, three moles of

P {C l}_{3}

and two moles of

{C l}_{2}

are taken in a closed vessel. If at equilibrium the vessel has

1.5

moles of

P {C l}_{5}

, the number of moles of

P {C l}_{3}

present in it is:

Q. In an evacuated closed isolated chamber at

250^{o} C

.02

mole

P {C l}_{5}

and

.01

mole

{C l}_{2}

are mixed

(P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2})

. At equilibrium density of mixture was

2.49 g / L

and pressure was

1

atm. The number of total moles at equilibrium will be approximately:

The equilibrium composition in 1 litre container for the reaction is
$P C l_{3} + C l_{2} ⇌ P C l_{5} 0.20 0.08 0.40$

0.22 mole of $C l_{2}$ is added at the same temperature and a new equilibrium is established. If the sum of the new equilibrium moles of $P C l_{3}, C l_{2} a n d P C l_{5}$ is p, then value of p is