A mixture of 10 cc of CO, 60 cc of $H_{2}$ , 25 cc of $C H_{4}$ are mixed with 750 cc of air ( $20 %$ oxygen) and ignited. Calculate the composition of the resultant mixture on cooling to room temperature.

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Solution

The following reactions will take place:
$2 C O + O_{2} \to 2 C O_{2}$
$2 H 2 + O_{2} \to 2 H_{2} O$
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
Hence, 10cc of CO will react with 5cc of $O_{2}$ , 60cc of $H_{2}$ will react with 30cc of $O_{2}$ and 25cc of $C H_{4}$ will react with 50cc of $O_{2}$ . Total $O_{2}$ used = 5 + 30 + 50 = 85cc
Composition of resulting mixture = 35 (10+ 25)cc of $C O_{2}$ , 110 (60 + 50)cc of $H_{2} O$ and 665cc of air.

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A mixture of 10 cc of CO, 60 cc of H2, 25 cc of CH4 are mixed with 750 cc of air (20% oxygen) and ignited. Calculate the composition of the resultant mixture on cooling to room temperature.

A mixture of 10 cc of CO, 60 cc of $H_{2}$ , 25 cc of $C H_{4}$ are mixed with 750 cc of air ( $20 %$ oxygen) and ignited. Calculate the composition of the resultant mixture on cooling to room temperature.