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Stoichiometric Calculations

A mixture of ...

Question

A mixture of $100 m m o l$ of $C a (O H)_{2}$ and $2 g$ of sodium sulphate was dissolved in water and the volume was made up to $100 m L$ . The mass of calcium sulphate formed and the concentration of $O H^{-}$ in resulting solution, respectively, are:
[Molar mass of $C a (O H)_{2}, N a_{2} S O_{4}$ and $C a S O_{4}$ are $74, 143$ and $136 g m o l^{- 1}$ , respectively; $K_{s p}$ of $C a (O H)_{2}$ is $5.5 \times 10^{- 6}]$

1.9 g, 0.14 m o l L^{- 1}

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13.6 g, 0.14 m o l L^{- 1}

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1.9 g, 0.28 m o l L^{- 1}

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13.6 g, 0.28 m o l L^{- 1}

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Solution

The correct option is C $1.9 g, 0.28 m o l L^{- 1}$

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Similar questions

68.4 g

A l_{2} (S O_{4})_{3}

500 m L

(A l^{3 +})

(S O_{4}^{2 -})

A l_{2} (S O_{4})_{3} = 342 g m o l^{- 1})

N a_{2} C O_{3}

N a^{+}

N a_{2} C O_{3} = 106 g m o l^{- 1}

K_{s p} = 9.1 \times 10^{- 6}

B a C l_{2}

B a S O_{4}

S O_{2} C l_{2}

C a (O H)_{2}

C a (O H)_{2}

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