wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A mixture of 100 mL of CO, CO2 and O2 was sparked. When the resulting gaseous mixture was passed through KOH solution, the contraction in volume was found to be 80 mL. The composition of the initial mixture may be (in the same order):

A
20 mL, 50 mL, 30 mL
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
40 mL, 20 mL, 40 mL
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
30 mL, 50 mL, 20 mL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30 mL, 40 mL, 30 mL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A 20 mL, 50 mL, 30 mL
B 40 mL, 20 mL, 40 mL
Let the initial volume of CO,CO2 and O2 be a, b and c respectively.

Then, a+b+c=100.........(i)

After the reaction, CO+12O2CO2 and the treatment with KOH, a contraction of 80 mL was observed.
This is due to the consumption of oxygen and the absorbtion of CO2
a+b+a2=80 ..............(ii)

Also,
ca2=20............ (iii)

The options should satisfy all the three equations.

a) a = 20 mL b = 50 mL c = 30 mL
It satisfies all the three equations.

b) a = 40 mL b = 20 mL c = 40 mL
It satisfies all the three equations.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon