Question

A mixture of $2$ moles $CO$ and $1$ mole $O_2$ in a closed vessel is ignited to convert $CO$ into $C{O}_2$. Then

• A. $\Delta H=\Delta E$
• B. $\Delta H>\Delta E$
• C. $\Delta H<\Delta E$
• D. none of the above

Answer 1

The correct option is C $\Delta H<\Delta E$

$2CO\left(g\right)+O_2\left(g\right)\to 2C{O}_2\left(g\right)$

$\Delta n_g=2-1-2$ $=-1$

$\Delta H=\Delta E+\Delta n_{g}RT$

$\therefore \Delta H=\Delta E-RT$

$\therefore \Delta H+RT=\Delta E$

$\therefore \Delta E>\Delta H$

Hence, option C is correct.