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Standard XII

Chemistry

Heat Capacity

a mixture of ...

Question

a mixture of 250g of water and 200g of ice at 0deg celcius is kept in a calorimeter (w=50g) if 200g of steam at 100 deg celcius is passed through the mixture then calculate the final temp and the mass of the contents of calorimeter.
please answer in detail and in simple language.

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Solution

Let the final temperature of the mixture = 100ºC.
Heat gained by ice and iced water Q1 is
Q1 = m•λ + m•c•ΔT = 200•80 + 200•1•100 = 3600 cal.
Q2 = (m1•c +W) •(100º -0º) =(250•1 + 50) •100 = 30000 cal.
Q =Q1+Q2 = 36000 +30000 = 66000 cal.
If entire steam condensed the total heat given by it is
Q3 = m•L = 200•540= 108000 cal.
Now the total heat available is 108000 cal, but only 66000 cal are required. Therefore? all the steam will not get condensed.
Final temperature of the mixture is 100ºC.
Mass of steam condensed is 66000/540=122.2 g.
Mass of the contents is 250 +200 + 122.2 = 572.2 g

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a mixture of 250g of water and 200g of ice at 0deg celcius is kept in a calorimeter (w=50g) if 200g of steam at 100 deg celcius is passed through the mixture then calculate the final temp and the mass of the contents of calorimeter. please answer in detail and in simple language.

a mixture of 250g of water and 200g of ice at 0deg celcius is kept in a calorimeter (w=50g) if 200g of steam at 100 deg celcius is passed through the mixture then calculate the final temp and the mass of the contents of calorimeter.
please answer in detail and in simple language.