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Characteristics of Equilibrium Constant

A mixture of ...

Question

A mixture of $3.8$ moles of $N O$ and $0.924$ moles of $C O_{2}$ was allowed to react in a $1.0 L$ container. The equilibrium mixture contains $0.124$ mole of $C O_{2}$ . Calculate $K_{c}$ for the reaction:
$N O_{(g)} + C O_{(2 (g)} ⇌ N O_{2 (g)} + C O_{(g)}$ .

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Solution

$N O (g) + C O_{2} (g) ⇌ N O_{2} (g) + C O (g) i n i t i a l m o l e s : 3.8 0.924 - - A t {e q}^{m} : 3.8 - 0.8 = 3 0.924 - 0.8 = 0.124 0.8 0.8 K_{C} = K_{n} (\frac{1}{V_{t o t a l}}) Δ n g = (\frac{0.8 \times 0.8}{3 \times 0.124}) = 1.72$

the correct answer is 1.72

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