A mixture of 70 litres of juice and water contains $10 %$ of water. How much water must be added to make the water content $12.5 %$ of the resulting mixture?

1 L

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2 L

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3 L

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4 L

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Solution

The correct option is B
2 L

Let the required quantity of water = x litres.

According to the question,
$70 \times \frac{10}{100} + x = (70 + x) \times \frac{12.5}{100}$

= $7 + x = (70 + x) \times 0.125$
= $7 + x = 8.75 + 0.125 x$
= $x - 0.125 x = 8.75 - 7$
= $0.875 x = 1.75$
$\Rightarrow x = 2$

2 litres of water must be added to make the mixture contain 12.5% of water

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A mixture of 70 litres of juice and water contains 10% of water. How much water must be added to make the water content 12.5% of the resulting mixture?

The correct option is B 2 L Let the required quantity of water = x litres. According to the question, 70×10100+x=(70+x)×12.5100 =7+x=(70+x)×0.125 =7+x=8.75+0.125x =x−0.125x=8.75−7 =0.875x=1.75 ⇒x=2 2 litres of water must be added to make the mixture contain 12.5% of water

A mixture of 70 litres of juice and water contains $10 %$ of water. How much water must be added to make the water content $12.5 %$ of the resulting mixture?