A mixture of 70 litres of wine and water contains 10% of water. What quantity of water must be added to make the water content 12.5% of the resulting mixture?
2 litre
Let the required quantity of water to be added be x litres.
Given that 10% of the original mixture is water:-
⇒ Water content in the original mixture =10100×70=7 litres
When x litres of water is added, the volume of the solution becomes 70 + x.
The new volume of water = water content in original solution + x
⇒ 7 + x
Given, 7+x=12.5100×(70+x)
⇒700+100x=875+12.5x
⇒87.5x=175
⇒x=17587.5=2
∴ 2 litres of water must be added to make the water content in the mixture 12.5%.