Question

A mixture of all isomers of pentane is allowed to react with chlorine radicals (produced by photochemical cleavage of $C{l}_2)$. How many different isomeric alkyl radicals can form by hydrogen abstraction in the following reaction?
Pentane (all isomers )$+C{l}^{\ast }\to$ Pentyl radicals (all isomers) $+HCl$

• A. $5$
• B. $6$
• C. $7$
• D. $8$

Answer 1

Answer: (D)

$8$

Pentane radicals (3)

Isopentane radicals (4)

Neopentane radicals (1)

So total 8 radicals are possible

Note-Consider removal of hydrogen from all unique positions.