Question

A mixture of boron trichloride and hydrogen is subjected to silent electric discharge to form ${}^{\prime }{A}^{\prime }$ and $HCl{.}^{\prime }{A}^{\prime }$ is mixed with $N{H}_3$ and heated to ${200}^{o}C$ to form ${}^{\prime }{B}^{\prime }$. The formula of ${}^{\prime }{B}^{\prime }$ is:

• A. $H_{3}B{O}_3$
• B. $B_2{O}_3$
• C. $B_2{H}_6$
• D. $B_3{N}_3{H}_6$

Answer 1

The correct option is D $B_3{N}_3{H}_6$

$2BC{l}_3+3H_2\underset{discharge}{\stackrel{electric}{}}\underset{\left(A\right)}{B_2{H}_6}+6HCl$.

$A$ is $B_2{H}_6.$

$B_2{H}_6+2N{H}_3\to B_2{H}_6.2N{H}_3\stackrel{{200}^{\circ }}{\to }{B}_3{N}_3{H}_6$

So $B$ is $B_3{N}_3{H}_6$.

Hence option D is correct