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Oxides of Sulphur

A mixture of ...

Question

A mixture of $C O$ and ${C O}_{2}$ has vapour density $20$ at STP, then $100 g$ of this mixture contains.

A

0.4

mole of

C O

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B

0.2

mole of

C O

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C

0.625

mole of

C O

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D

0.375

mole of

C O

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Solution

The correct option is C $0.625$ mole of $C O$
The mixture of CO and CO $_{2}$ has vapour density (V.D.) $20$ at STP.

Total weight of the mixture = $100 g .$

Let weight of CO = $x g .$

Then weight of CO2 will be $(100 - x) g .$

We know that Molar mass $M . M .$ = $\frac{V . D .}{2}$

$M . M .$ of the mixture = $40 g .$

Now, because no of moles(n)= Given mass/ $M . M .$

Thus $n_{C O 2} = \frac{100 - x}{44}$

$n_{m i x} = \frac{100}{40} = 2.5$

$n_{C O} + n_{C O_{2}} = n_{m i x}$

$\frac{x}{28} + \frac{(100 - x)}{44} = 2.5$

$x = 0.625$

Hence, (c) is the correct answer.

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