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Standard XII

Chemistry

Stoichiometric Calculations

A mixture of ...

Question

A mixture of $C u O$ and ${C u}_{2} O$ contains $88 %$ of $C u$ . The percentage of $C u O$ in the mixture is (as nearest integer) :

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Solution

Let the mass of mixture be $100$ g.
Mass of $C u O$ = $x$ g
Mass of $C u_{2} O = y$ g
So, mass of oxygen $= \frac{16 x}{79.5} + \frac{16 y}{143} = 12$ g
Similarly, mass of $C u = \frac{63.5 x}{79.5} + \frac{127 y}{143} = 88$ g
so, $x = 8.65 %$ and $y = 91.35 %$
Therefore, the nearest integer is $9 %$ .

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A mixture of CuO and Cu2O contains 88% of Cu. The percentage of CuO in the mixture is (as nearest integer) :

Let the mass of mixture be 100 g.Mass of CuO = x gMass of Cu2O=y gSo, mass of oxygen =16x79.5+16y143=12 gSimilarly, mass of Cu=63.5x79.5+127y143=88 gso, x=8.65% and y=91.35%Therefore, the nearest integer is 9%.

A mixture of $C u O$ and ${C u}_{2} O$ contains $88 %$ of $C u$ . The percentage of $C u O$ in the mixture is (as nearest integer) :