CameraIcon

SearchIcon

MyQuestionIcon

46

You visited us 46 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

A mixture of ...

Question

A mixture of $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4}$ (oxalic acid) and some inert impurity weighing $3.185 g$ was dissolved in water and the solution made up to $1 L$ , $10 m L$ of this solution required $3 m L$ of $0.1 N N a O H$ for complete neutralization. In another expriment $100 m L$ of the same solution in hot condition required $4 m L$ of $0.02 M K M n O_{4}$ solution for complete reaction. The weight percentage of $H_{2} S O_{4}$ in the mixture was:

Open in App

Solution

Let x and y are milli moles $H_{2} S O_{4}$ and $H_{2} C_{2} O_{4}$ in given mixture when both reacted with base
m eq. of acids = m eq. of base;
$(x + y) \times 2 = 3 \times 0.1 \times \frac{1000}{10}$
$\Rightarrow x + y = 15$
In second experiment only $K M n O_{4}$ reacted with $H_{2} C_{2} O_{4}$ in which $M n^{7 +}$ converted into $M n^{2 +}$ and $C_{2} O_{4}^{2 -}$ converted into $C O_{2}$
$∴$
$milli equivalent of H_{2} C_{2} O_{4} = milli equivalent of K M n O_{4}$
$y \times 2 = 4 \times 0.02 \times 5 \times \frac{1000}{100} y = 2 ∴ x = 13, w e i g h t o f H_{2} S O_{4} = 13 \times 10^{- 3} \times 98 = 1.274 g$
weight % of $H_{2} S O_{4}$ in sample $= \frac{1.274}{3.185} \times 100 = 40 %$

Suggest Corrections

thumbs-up

1

Similar questions

Q. A mixture of

H_{2} S O_{4}

H_{2} C_{2} O_{4}

(oxalic acid) and some inert impurity weighing

3.185 g

was dissolved in water and the solution made up to

1 L

10 m L

of this solution required

3 m L

0.1 N N a O H

for complete neutralization. In another expriment

100 m L

of the same solution in hot condition required

4 m L

0.02 M K M n O_{4}

solution for complete reaction. The weight percentage of

H_{2} S O_{4}

in the mixture was:

Q. A mixture of

H_{2} S O_{4}

H_{2} C_{2} O_{4}

(oxalic acid) and some inert impurity weighing

3.822

g was dissolved in water and the solution made up to

1

10

mL of this solution requires

3

0.1

N a O H

for complete neutralization. In another experiment

100

mL of the same solution in hot condition requires

4

0.02

K M n O_{4}

solution for complete reaction. The wt. % of

H_{2} S O_{4}

in the mixture was:

Q. A mixture of

H_{2} C_{2} O_{4}

(oxalic acid) and

N a H C_{2} O_{4}

2.02 g

was dissolved in water and the solution made upto

1

10

mL of the solution required

3.0

0.1 N

sodium hydroxide solution for complete neutralisation. In another experiment,

10.0

mL of the same solution in hot dilute sulphuric acid medium required

4.0

0.1

N potassium permanganate solution for complete reaction. Calculate the amount of

H_{2} C_{2} O_{4}

Q. A mixture of

H_{2} C_{2} O_{4}

N a H C_{2} O_{4}

2.02

g was dissolved in water and the solution made upto one litre.

10

mL of this solution required

3

0.1 N N a O H

solution for complete neutralization. In another experiment,

10

mL of the same in hot dilute

H_{2} S O_{4}

medium required

4

0.1 N K M n O_{4}

for complete neutralization. Calculate the mass of

N a H C_{2} O_{4}

in mixture (as nearest integer).

Q. A mixture of

H_{2} C_{2} O_{4}

N a H C_{2} O_{4}

2.02 g

was dissolved in water and the solution made up to one litre.

10 m L

of this solution required

3.0 m L

0.1 N N a O H

solution for complete neutralisation. In another experiment

10 m L

of same solution in hot dilute

H_{2} S O_{4}

medium required

4 m L

0.1 N K M n O_{4}

for complete neutralisation. Calculate the amount of

H_{2} C_{2} O_{4}

N a H C_{2} O_{4}

in the mixture.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Stoichiometric Calculations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Stoichiometric Calculations

Standard XI Chemistry

Join BYJU'S Learning Program

CrossIcon