A mixture of hydrogen and chlorine occupying 36cc was exploded. On shaking it with water, 4cc of hydrogen was left behind. Find the composition of the mixture.

Open in App

Solution

Hydrogen and chlorine when reacted together form Hydrogen chloride (HCl).
$H_{2} + C l_{2} \to 2 H C l$
When mixed with water, HCl dissolves in water.
$H C l + H_{2} O \to H_{3} O + C l^{-}$
Now, the point is, that the excess hydrogen left after dissolving in water is the unreacted hydrogen.

Now, $H_{2} + C l_{2} \to 2 H C l$
So, 1 mole of $H_{2}$ reacts with $C l_{2}$
1 mole of every gas occupies 22.4 litres at room teperature.

So, 22.4 litre of $H_{2}$ reacts with $C l_{2}$
1 litre of $H_{2}$ reatcs with $C l_{2}$
1 cc of $H_{2}$ reacts with 1 cc of $C l_{2}$
Total volume initially was 36 cc, and $H_{2}$ left at last was 4 cc.

So, 36 - 4 =32 cc of volume of mixture reacted.
1 cc of $H_{2}$ reacts with 1 cc of $C l_{2}$ , so out of the 32 cc 16 cc was $H_{2}$ and 16 cc was $C l_{2}$
So, mixture had 16 + 4 = 20 cc $H_{2}$ and 16 cc of $C l_{2}$

Suggest Corrections

Similar questions

A mixture of hydrogen and chlorine occupying $36 c m^{3}$ exploded. On shaking it with water, $4 c m^{3}$ of hydrogen was left behind. Find the composition of the mixture

A mixture of hydrogen and chlorine occupting $36 c m^{3}$
was exploded. On shaking it with water, $4 c m^{3}$ fo hydrogen was left behind. Find the composition of the mixture.