Question

A mixture of $L{i}_{2}C{O}_3$ and $K_{2}C{O}_3$ on strong heating gave 0.25 mole of $C{O}_2$. The mole $\%$ of $L{i}_{2}C{O}_3$ and $C{O}_2$ in the mixture is :

• A. $L{i}_{2}C{O}_3:25\%K_{2}C{O}_3:75\%$
• B. $L{i}_{2}C{O}_3:75\%K_{2}C{O}_3:25\%$
• C. $L{i}_{2}C{O}_3:60\%K_{2}C{O}_3:40\%$
• D. $L{i}_{2}C{O}_3:40\%K_{2}C{O}_3:60\%$

Answer 1

The correct option is A $L{i}_{2}C{O}_3:25\%K_{2}C{O}_3:75\%$

$L{i}_{2}C{O}_3:25\%K_{2}C{O}_3:75\%$

($C{O}_2$ is due to $L{i}_{2}C{O}_3$ only.

$L{i}_{2}C{O}_3\stackrel{\Delta }{\to }L{i}_{2}O+C{O}_2$

$K_{2}C{O}_3\stackrel{\Delta }{\to }$ no effect)
Hence option A is correct.