A mixture of methane and ethyne in the volume ratio x:y has a total volume of 30mL. On complete combustion it gave 40 mL of CO2 if the ratio had been y:x what volume of CO2 would have been obtained?
A
100mL
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B
60mL
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C
50mL
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D
150mL
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Solution
The correct option is C50mL Let volume of methane = xmL than volume of ethylene = ymL given x+y=30mL ...(1) On complete combustion of mixture CH4xmL+O2→CO2xmL+2H2OC2H4ymL+3O2→2CO22ymL+2H2O Total vol. of CO2 produced =x+2ymL ∴x+2y=40...(2) from (1) and (2) x=20 and y=10mL If ratio had been y:x than vol of CH4=y mL and vol of C2H4=x mL on combustion C2H4ymL+O2→CO2ymL+2H2OC2H4xmL+3O2→2CO22xmL+2H2O ∴ Total CO2 formed =(y+2x)mL=10+2(20)=50mL