A mixture of $N_{2}$ and water vapours is admitted into a flask which contains a solid drying agent. Immediately after admission, the pressure of the flask is 760 mm. After standing some hours, the pressure reaches a steady value of 745 mm.
Calculate the composition of $H_{2} O$ in mole % of original mixture (as nearest integer).

Open in App

Solution

Given, $P_{N_{2}}^{'} + P_{H_{2} O}^{'} = 760 m m$
After the use of drying agent, $H_{2} O$ are absorbed
$P_{N_{2}}^{'} = 745 m m$
$P_{H_{2} O}^{'} = 760 - 745 = 15 m m$
$P_{N_{2}}^{'} = P_{M} \times$ mole fraction of $N_{2}$
mole fraction of $N_{2} = \frac{P_{N_{2}}}{P_{M}} = \frac{745}{760} = 0.9803$
% mole fraction of $N_{2} = 98.03$ %
% mole fraction of $H_{2} O = 1.97$ %
so nearest integer value is 2.

Suggest Corrections

Similar questions

Q. A mixture of

N_{2}

and water vapours is admitted to a flask which contains a solid drying agent. Immediately after admission, the pressure of the flask is 760 mm. After standing some hours, the pressure reached a steady value of 745 mm.
Calculate the composition of

N_{2}

in mole % of original mixture (as nearest integer)

Q. A mixture of

N_{2}

and water vapours is admitted into a flask which contains a solid drying agent. Immediately after admission, the pressure of the flask is 760

t o r r

. After standing some hours, the pressure reaches a steady value of 745

t o r r

.
If the experiment is conducted at

20^{o} C

and the drying agent increases its mass by 0.15

g

, the volume becomes

X \times 10

litre. The value of X is _______.

[Neglect volume occupied by drying agent.]

Q. A mixture of nitrogen and water vapours is admitted to a flask which contains a solid drying agent immediately after admission, the pressure of the flask is 760 mm. After some hours the pressure reached a steady value of 745 mm.
(a) Calculate the composition, in mol and percent of original mixture.
(b) If the experiment is done at

20^{0} C

and the drying agent increases in weight by 0.15 g. What is the volume of the flask? (the volume occupied by the drying agent may be ignored)?

Q. A mixture of nitrogen and water vapours is admitted to a flask at

760 t o r r

which contains a sufficient solid drying agent after long time the pressure reached a steady value of

722 t o r r

. If the experiment is done at

27^{\circ} C

and drying agent increases in weight by

0.9 g m

, what is the volume of the flask? Neglect any possible vapour pressure of drying agent and volume occupied by drying agent.

A mixture of nitrogen and water vapours is admitted to a flask at 760 torr which contains a sufficient solid drying agent after long time the pressure reached a steady value of 722 torr. If the experiment is done at 27 $^{\circ}$ C and drying agent increases in weight by 0.9 gm, what is the volume of the flask? Neglect any possible vapour pressure of drying agent and volume occupied by drying agent.

Join BYJU'S Learning Program

Given, P′N2+P′H2O=760mmAfter the use of drying agent, H2O are absorbedP′N2=745mmP′H2O=760−745=15mmP′N2=PM× mole fraction of N2mole fraction of N2=PN2PM=745760=0.9803% mole fraction of N2=98.03%% mole fraction of H2O=1.97%so nearest integer value is 2.