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Stoichiometric Calculations

A mixture of ...

Question

A mixture of $N a_{2} C O_{3}$ and $N a H C O_{3}$ having a total weight of $100$ g, on heating, produced $11.2$ L of $C O_{2}$ under STP conditions. The percentage of $N a_{2} C O_{3}$ in the mixture is:

58 %

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44.2 %

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84 %

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16 %

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Solution

The correct option is A $58 %$
$N a_{2} C O_{3}$ does not decompose on heating.
Two moles of $N a H C O_{3}$ decomposes on heating to give two moles of $C O_{2}$ .
$11.2$ L of $C O_{2}$ corresponds to $0.5$ moles of $N a H C O_{3}$ (molecular weight is $84$ g/mol) which corresponds to $42$ g.
Hence, the percentage of $N a_{2} C O_{3}$ in the mixture is $\frac{100 - 42}{100} \times 100 = 58 %$ .

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