Question

A mixture of non reacting gases exert a pressure of $5atm$. If one of the gases occupy $40$% volume of the mixture, what would be its partial pressure in atm?

Answer 1

Volume percent can be approximated to mole percent as volume is directly proportional to the number of moles.

Volume percent of the gas $=40$ %

Mole percent of the gas $=40$ %

Mole fraction of the gas $=\frac{40}{100}=0.4$

The partial pressure of a gas is the product of its mole fraction and total pressure. It is
$=0.4\times 5atm=2atm$.

Hence, the partial pressure of the gas is 2 atm.