A mixture of potassium carbonate and calcium carbonate is subjected to decomposition. The percentage loss in weight was 11%. The ratio of amount of potassium carbonate to calcium carbonate in the mixture is:

3:1

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1:3

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2:1

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1:2

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Solution

The correct option is A 3:1
As we know, potassium carbonate does not decompose on heating. Calcium carbonate decomposes to give $C a O$ and $C O_{2}$ and loss in weight is equal to the amount of $C O_{2}$ formed.
Let weight of mixture $= 100$ g.
Loss in weight $=$ Amount of $C O_{2}$ formed $= 11$ g
$44$ g $C O_{2}$ is formed from $100$ g $C a C O_{3}$
$11$ g $C O_{2}$ is formed from $= \frac{11 \times 100}{44}$ $= 25$ g $C a C O_{3}$
Weight of $K_{2} C O_{3}$ in the mixture $= 100 - 25 = 75$ g
Ratio of $K_{2} C O_{3}$ and $C a C O_{3} = 75 : 25 = 3 : 1$

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