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Question

A mixture of two immiscible liquids nitrobenzene and water boiling at 97oC has a partial vapor pressure of water 733 mm and that of nitrobenzene 27 mm. The ratio of the weights of water to nitrobenzene in the distillate is:

A
4
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B
5
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C
3
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D
7
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Solution

The correct option is A 4
P=PM×χA where χA is the mole fraction in the gaseous phase
27=PM×W2123W118×W2123 (for nitrobenzene) .............(1)

733=PM×W118W118×W2123 (for water) .............(2)
On dividing equation 2 by equation 1, we get-

73327=W118×123W2

W1W2=4

Hence, option A is correct.

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