A mixture upon adding $c o n c . H_{2} S O_{4}$ gives orange red fumes. It may contain the anion pair :

C r O_{4}^{2 -} + C l^{-}

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B r^{-} + C l^{-}

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N O_{3}^{-} + C l^{-}

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C r O_{4}^{2 -} + N O_{3}^{-}

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Solution

The correct option is A $C r O_{4}^{2 -} + C l^{-}$
When a mixture containing chloride ion is heated with $K_{2} C r_{2} O_{7}$ and concentrated $H_{2} S O_{4}$ , deep orange red fumes of chromyl chloride $(C r O_{2} C l_{2})$ are formed.
$K_{2} C r_{2} O_{7} + 4 N a C l + 6 H_{2} S O_{4} \to 2 K H S O_{4} + 4 N a H S O_{4} + 2 C r O_{2} C l_{2} ↑ O r a n g e - r e d f u m e s + 3 H_{2} O$
Also,
$2 C r O_{4}^{2 -} + 2 H^{+} Y e l l o w \to C r_{2} O_{7}^{2 -} O r a n g e + H_{2} O$
The anion may contain $C r O_{4}^{2 -}$ and $C l^{-}$

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Similar questions

H_{2} {S O}_{4}

C l O^{-} + C r (O H)_{4}^{-} \to C r O_{4}^{2 -} + C l^{-}

0.1 M

{C l}^{-}

0.001 M

C r O_{4}^{2 -}

A g {N O}_{3}

A g C l

{A g}_{2} C r O_{4}

K_{s p} A g C l = 1.7 \times 10^{- 10} M^{2}

K_{s p} {A g}_{2} C r O_{4} = 1.79 \times 10^{- 12} M^{3}

{C l}^{-}

C r O_{4}^{2 -}

C r (O H)_{3} + C l O^{-} + O H^{-} \to C r O_{4}^{2 -} + C l^{-} + H_{2} O

N O_{3}^{-}

C l^{-}

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