A moist sand occupies a depth of 15 cm and when fully saturated it occupies 12 cm. Then the bulking of stand is :

12 %

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25 %

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15 %

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10 %

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Solution

The correct option is B 25 %
Given data-

Moist sand depth = $15 cm$

fully saturated sand depth = $12 cm$

bulking of sand $= \frac{15 - 12}{12} \times 100$

$= 25 %$

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