A molecule A2B Mol- Wt - 166-4occupies triclinic lattice with a - 5-5em-A- b - 8-5em-A and c - 4-5em-A- If the density of A2B is 5-2 g-cm-3- the number of molecules present in one unit cell is-

Volume of the unit cell = a × b × c × = 5 × 10^ 8 × 8 × 10^ 8 × 4 × 10^ 8 cm^3 = 1.6 × 10^ 22cm^3 Mass of the unit cell = 1.6 × 10^ 22 × 5.2 = 8.32 × 10^ 22g ...

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Byju's Answer

Standard XII

Chemistry

Density

A molecule A2...

Question

A molecule $A_{2} B$ ( $M o l . W t = 166.4)$ occupies triclinic lattice with a = 5 $\circ A$ , b = 8 $\circ A$ and c = 4 $\circ A$ . If the density of $A_{2} B$ is $5.2 g . c m^{- 3}$ , the number of molecules present in one unit cell is:

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Solution

The correct option is B 3
Volume of the unit cell = $a \times b \times c \times$ =
$5 \times 10^{- 8} \times 8 \times 10^{- 8} \times 4 \times 10^{- 8} c m^{3}$

$= 1.6 \times 10^{- 22} c m^{3}$

Mass of the unit cell = $1.6 \times 10^{- 22} \times 5.2 = 8.32 \times 10^{- 22} g$

Number of molecules in one unit cell = $\frac{8.32 \times 10^{- 22} g \times 6 \times 10^{23} m o l^{- 1}}{166.4 g . m o l^{- 1}}$

$= 3$

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Similar questions

Q. A molecule,

A_{2} B

(molecular weight

= 166.4

g/mol) occupies triclinic lattice with

a = 5 ˚ A, b = 8 ˚ A

and

c = 4 ˚ A

. If the density of

A_{2} B

5.2

g cm

^{- 3}

, the number of molecules present in one unit cell is__________.

Q. A molecule

A_{2} B

(molar mass = 166.4) occupies a triclinic lattice with a =

5 \circ A

, b =

8 \circ A

, and c =

4 \circ A

. If the density of

A_{2} B

is 5.2

g c m^{- 3}

, the number of molecules present in one unit cell is:
(Take

N_{A} = 6 \times 10^{23}

)

Q. A molecule

A_{2} B

(

M o l . W t = 166.4)

occupies triclinic lattice with a = 5

\circ A

, b = 8

\circ A

and c = 4

\circ A

. If the density of

A_{2} B

5.2 g . c m^{- 3}

, the number of molecules present in one unit cell is:

A_{2} B

molecules (molar mass

= 259.8

g/mol ) crystallizes in a hexagonal lattice.The lattice constants are

a = 5

˚ A

and

b = 8

˚ A

. If the density of crystal is

5

g cm

^{- 3}

, then how many molecules are contained in a given unit cell? (use

N_{A} = 6 \times 10^{23}

)

A_{2} B

molecules (molar mass =259.8 g/mol) crystallises in a hexagonal lattice as shown in figure. The lattice constants were

a = 5 ˚ A

and

b = 8 ˚ A

. If density of crystal is 5

g / c m^{3}

then how many molecules are contained in given unit cell? (use

N_{A} = 6 \times 10^{23}

)

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A molecule A2B (Mol.Wt = 166.4)occupies triclinic lattice with a = 5∘A, b = 8∘A and c = 4∘A. If the density of A2B is 5.2 g.cm−3, the number of molecules present in one unit cell is:

The correct option is B 3Volume of the unit cell = a × b × c × = 5 × 10−8 × 8 × 10−8 × 4 × 10−8 cm3 = 1.6 × 10−22cm3 Mass of the unit cell = 1.6 × 10−22 × 5.2 = 8.32 × 10−22g Number of molecules in one unit cell = 8.32 × 10−22g×6×1023mol−1166.4 g.mol−1 =3

A molecule $A_{2} B$ ( $M o l . W t = 166.4)$ occupies triclinic lattice with a = 5 $\circ A$ , b = 8 $\circ A$ and c = 4 $\circ A$ . If the density of $A_{2} B$ is $5.2 g . c m^{- 3}$ , the number of molecules present in one unit cell is: