A molecule A2B (Mol.Wt=166.4)occupies triclinic lattice with a = 5∘A, b = 8∘Aand c = 4∘A. If the density of A2B is 5.2g.cm−3, the number of molecules present in one unit cell is:
A
2
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B
3
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C
4
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D
5
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Solution
The correct option is B 3 Volume of the unit cell = a×b×c× = 5×10−8×8×10−8×4×10−8cm3
=1.6×10−22cm3
Mass of the unit cell = 1.6×10−22×5.2=8.32×10−22g
Number of molecules in one unit cell = 8.32×10−22g×6×1023mol−1166.4g.mol−1