A molecule having three differential chiral carbon atoms, how many stereoisomers it will have?

8

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3

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9

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6

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Solution

The correct option is A $8$
The number of stereoisomers $= 2^{n}$
(Here, $n =$ Chiral carbon atom)
Thus, the number of stereoisomers $= 2^{3} = 8$ .

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C H_{3} C H = C H C H_{2} C H B R C H_{3}

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{C H}_{3} C H = {C H C H}_{2} {C H B r C H}_{3}

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