A molecule may be represented by three structures having energies E1,E2 and E3, repectively. The energies of these structure follow the order E3<E2<E1 repectively. If the experimental bond energy of the molecule is E0, the resonance energy is:
A
(E1+E2+E3)−E0
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B
Eo−E3
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C
E3−E1
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D
E0−E2
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Solution
The correct option is BEo−E3 Resonance hybrid is the average or hybrid of these resonance structures. Resonance energy = Eo− smallest energy of lewis structure = Eo−E3 Option B is correct.